25
07/2014
c#用JObject解析Json
1、下载库：http://json.codeplex.com/
2、添加相应库到项目中。参考：vs2013中c#引用第三方库
3、添加引用：using Newtonsoft.Json.Linq;
4、相关方法：
（1）遍历Json对象
JObject _jObject = JObject.Parse("{'ID':'001','Name':'test','Mark':'Hello Word'}");
foreach (JProperty item in _jObject.Children())
{
str.Append(item.Name + "---" + item.Value+"\n");
}
/**************************************/
_jObject = JObject.Parse("{ID:{ID1:{ID2:'value',name:'valueName'}},'Name':'test','Mark':'Hello Word'}");
var _value = _jObject["ID"]["ID1"]["ID2"].ToString(); //取值（2）注意还有数组类型的Json对象，用JArray和JObject配合使用
JArray ja = JArray.Parse(@"[{""Name"":""lj"",""Age"":12}, {""Name"":""cy"",""Age"":28}]");
for (int i = 0; i < ja.Count; i++)
{
JObject jo = JObject.Parse(ja[i].ToString());
Console.WriteLine(jo["Name"].ToString());
Console.WriteLine(jo["Age"].ToString());
}
Console.ReadKey();转载请注明：康瑞部落 » c#用JObject解析Json
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