29
04/2015
[LeetCode] Isomorphic Strings
Isomorphic Strings
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
解题思路:
这道题是判断两个单词是否同构。这里的同构的意思是,对于例子egg和add,若存在一个映射,e->a,g->d,单词egg和add同构。注意,不可以多个字符映射到同一个字符中去,比如aa和ab。因此要有两个hash表来记录。由于是字符,不会超过256个,因此可以用数组来记录这种映射。
class Solution { public: bool isIsomorphic(string s, string t) { int len1=s.length(); int len2=t.length(); if(len1!=len2){ return false; } char charMap[256]; char charMap1[256]; memset(charMap, 0, sizeof(char)*256); memset(charMap1, 0, sizeof(char)*256); for(int i=0; i<len1; i++){ if(charMap[s[i]]==0){ charMap[s[i]] = t[i]; }else if(charMap[s[i]]!=t[i]){ return false; } if(charMap1[t[i]]==0){ charMap1[t[i]] = s[i]; }else if(charMap1[t[i]]!=s[i]){ return false; } } return true; } };
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